Question

(x+5) (x-1) = 6 in ax+bx+c=0​

Answer 1

$\green{\bold{\underline{ ☆ UPSC-ASPIRANT ☆} }}$

$\red{\bold{\underline{\underline{QUESTION:-}}}}$

(x+5) (x-1) = 6 in ax+bx+c=0

$\huge\bigstar\huge\tt\underline\red{ᴀɴsᴡᴇʀ }\bigstar$

$➫(x + 5)(x - 1) = 6$

$➫ {x}^{2} - x + 5x - 5 = 6$

$➫ {x}^{2} + 4x - 5 - 6 = 0$

$➫ {x}^{2} + 4x - 11 = 0$

It is in the form ax+bx+c=0

---->>>>>>Here is your answer<<<<--------

HOPE IT HELPS YOU..

_____________________

Thankyou:)