(x+5)(x-1)=6 in the form of ax2+bx+c=0
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Answer:
1x²-6x-1=0
Step-by-step explanation:
multiply brackets
x²-x-5x+5=6
-x and -5x becomes -6x so
x²-6x+5=6
bring 6 on left side
x²-6x+5-6=0
+5-6 becomes -1 so
x²-6x-1=0
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