Question

(x+5)(x+2):factorise with suitable identity​

Answer 1

Given :

• ( x + 5 ) ( x + 2 )

Identity used :

• ( x + a ) ( x + b ) = x² + ( a + b )x + ab

Solution :

➨ ( x + 5 ) ( x + 2 )

➨ x² + ( 5 + 2 )x + 5*2

➨ x² + ( 7 )x + 10

➨ x² + 7x + 10

Other important identities :

• ( a + b )² = a² + 2ab + b²

• ( a - b )² = a² - 2ab + b²

Answer 2

✯✯ QUESTION ✯✯

$(x+5)(x+2)$

Factorise with suitable identity..

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✰✰ ANSWER ✰✰

$\textbf{(x+5)(x+2)}$

Using Identity : -

$⇢(x+a)(x+b)={x}^{2}+(a+b)x+ab$

$⇢(x+5)(x+2)$

$⇢{x}^{2}+(5+2)x+5×2$

☛$\large{\boxed{\bold{\bold{\green{\sf{{x}^{2}+7x+10}}}}}}$

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➜(a + b)²= a² + 2ab + b²

➜a²– b²= (a + b)(a – b)