Math, asked by warstonegaming2617, 9 months ago

x^5 - x^4 + 3x^3 + 4x^2 + 4x + 6 by x^2 + 1​

Answers

Answered by Anonymous
1

Answer:

5

−x

4

+3x

3

+4x

2

+4x+6÷x

2

+1

view step

To add or subtract expressions, expand them to make their denominators the same. Multiply x^{5}-x^{4}+3x^{3}+4x^{2}+4x+1x

5

−x

4

+3x

3

+4x

2

+4x+1 times \frac{x^{2}}{x^{2}}

x

2

x

2

.

\frac{\left(x^{5}-x^{4}+3x^{3}+4x^{2}+4x+1\right)x^{2}}{x^{2}}+\frac{6}{x^{2}}

x

2

(x

5

−x

4

+3x

3

+4x

2

+4x+1)x

2

+

x

2

6

Step-by-step explanation:

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