Question

X/5 + Y/15 = 1/3 ...(1)
X/3 + Y/5 = 1/5 ...(2)

Solve Using Cross-Multiplication Method.

Answer 1

$\frac{x}{5} + \frac{y}{15} = \frac{1}{3} \\ 15x + 5y = \frac{1}{3} \times 75 \\ 15x + 5y = 25 \\ divide \: both \: sideswith \: 5 \\ 3x + y = 5......1$
$\frac{x}{3} + \frac{y}{5} = \frac{1}{5} \\ 5x + 3y = \frac{1}{5} \times 15 \\ 5x + 3y = 3....2$
multiply 1 with 3
9x+3y = 15 .....3
subtract 2 and 3
$5x + 3y = 3 \\ - 9x - 3y = - 15 \\ - 4x = - 12 \\ x = \frac{12}{4} \\ x = 3$
put x=3 in 1
$3 \times 3 + y = 5 \\ y = 5 - 9 \\ y = - 4$
Therefore ( x, y ) ( 3,-4)

Answer 2

Answer:

X/5 + Y/15 = 1/3 ...(1)

X/3 + Y/5 = 1/5 ...(2)

Solve Using Cross-Multiplication Method.

Step-by-step explanation:

solved