Question

x +5y= 20,x+ 3y = 12 solve for x and y​

Answer 1

$\sf\large\blue{hope\:this\:helps\:u}$

$\sf\large\underline\pink{Given:}$

x +5y= 20-----eq(1)

x+ 3y = 12---------eq (2)

$\sf\large\underline\red{to\:find}$

x and y

$\sf\large\underline\green{solution:}$

subtract eq(2) from(1)

x +5y= 20

x+ 3y = 12

(-) (-)      (-)

---------------

2y = 8

$\frac{8}{2}$=4

$\boxed{y\:=\:4}$

sub y =4 in eq(1)

x = 20-5y

= 20-5*4

= 20*20

x=0

$\boxed{x\:=\:0}$

Answer 2

Answer:

y=4

x=0

Step-by-step explanation:

x+5y=20------1

x+3y=12-------2

__________

x+5y=20

-x-3y= -12

__________

0 + 2y=8

y=8/2

y=4

substitute equation y=4 in 1

x+5(4)=20

x+20=20

x=20-20

x=0

substitute equation y=4 in 2

x+ 3(4)=12

x+12=12

x=12-12

x=0