Question

x^6 - 1

plzz solve this....!!​

Answer 1

Answer:

x6−1 x 6 - 1. Rewrite x6 x 6 as (x2)3 ( x 2 ) 3 . (x2)3 −1 ( x 2 ) 3 - 1. Rewrite 1 1 as 13 1 3 . (x2)3−13 ( x 2 ) 3 - 1 3. Since both terms are perfect cubes, ...

Answer 2

Answer:

(x - 1)(x^2 + x + 1)(x + 1)(x^2 -x + 1)

Step-by-step explanation:

x^6 - 1

(x^3 - 1)(x^3 + 1)

$x ^{2} - y^{2} = (x + y)(x - y)$

(x - 1)(x^2 + x + 1)(x + 1)(x^2 -x + 1)

${x}^{3} - {y}^{3} = (x - y)(x ^{2} + xy + y ^{2} )$

${x}^{3} + {y}^{3} = (x + y)(x ^{2} - xy + y ^{2} )$