Math, asked by nadeemnawaz, 2 months ago

(x+6)^2 = (x+3)^2 + x^2​

Answers

Answered by Anonymous
1

Answer:

 {(x + 6)}^{2}  =  {(x + 3)}^{2}  +  {x}^{2} \\  {x}^{2}   +  {6}^{2}  =  {x}^{2}  +  {3}^{2}  +  {x}^{2}   \\ {x}^{2}  + 36 =  {x}^{4}  + 9 \\  {x}^{2}  -  {x}^{4}  = 9 - 36 \\  {\cancel - x}^{2}  =  \cancel- 27 \\  {x}^{2}  = 27 \\ x =  \sqrt{27 }  \\\boxed{ x = 5.19}

Answered by Joshuawall
0

Answer:

X1 = -3 and X2 = 9

Step-by-step explanation:

 ({x + 6})^{2}  = ( {x + 3)}^{2}  +  {x}^{2}

1ST STEP: EXPAND EQUATION BASE ON POWER/EXPONENT

  {x}^{2}  + 12x  + 36 =  {x}^{2}  + 6x  + 9+  {x}^{2}

2ND STEP: ELIMINATE THE EQUATION ON THE LEFT SIDE BY SUBTRACTING ITS TERMS BUT IN NEGATIVE FORM.

NOTE: APPLY THE LAW OF MATHEMATICAL EQUATIONS, " WHAT YOU ADDED OR SUBTRACTED IN ON ONE SIDE OF THE EQUATION WILL BE COPIED ON THE OTHER SIDE OF THE EQUATION"

  {x}^{2}  + 12x  + 36 - {x}^{2}   -  12x   - 36 =  {x}^{2}  + 6x  + 9+  {x}^{2} - {x}^{2}   -  12x   - 36

3RD STEP: COMBINE SIMILAR TERMS ON BOTH SIDES.

  0 =  {x}^{2}  + 6x  - 12x  + 9  - 36

  0 =  {x}^{2}  - 6x - 27

4TH STEP: FACTOR THE EQUATION

0= (x + 3) (x - 9)

5TH STEP: EQUATE BOTH FACTORS TO ZERO

x + 3 = 0

X1 = - 3

x - 9 = 0

X2 = 9

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