Question

X^6+32x^3-64 factorise

Answer 1

$x {}^{6} + 32 {x}^{3 } - 64$
=> (x^2)^3 + (2x) ^3 + (-4)^3 - 3(x^2)(2x) (-4)

let see is it right or wrong;
(x^2)^3

(2x) ^3 = 8x^3 and -3(x^2)(2x) (-4)=24x^3

so, (2x)^3 - 3(x^2)(2x) (-4)= 8x^3 + 24x^3 = 32x^3

(-4)^3 = -64

NOW,
=> (x^2)^3 + (2x) ^3 + (-4)^3 - 3(x^2)(2x) (-4)

=> (x^2 + 2x - 4) (x^4 + 4x^2 + 16- 2x^3 + 8x + 4x^2)


hope it's help you ✌✌✌