Question

x=√6+√6+√6 find the value of x​

Answer 1

Step-by-step explanation:

let x=root6+root6........infinitt

by squaring

x2=6+root6+root6.....

x2=6+x

x2-x-6=0

x2-3x+2x-6=0

x(x-3)+2(x-3)=0

(x-3)(x+2)=0

x=3,x=-2

Answer 2

Step-by-step explanation:

$3 \sqrt[2]{6}$