Question

x+6 is a factor of p(x)=x³+3x²+4x+k
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Answer 1

x = -6

${x}^{3} + 3 {x}^{2} + 4x + k \\ { - 6}^{3} + 3 \times { - 6}^{2} + 4 \times - 6 + k = 0 \\ - 216 + 108 - 24 + k = 0 \\ - 132 + k = 0 \implies \: k = 132$