Math, asked by potevishal817, 19 days ago

x(х+6) (x+2)^2 (x-3) >0

Answers

Answered by harshitac8b20

0

Answer:

(x - 2) + 2(x - 2)/(x - 2) (x - 1) = 6/x. ⇒ 3x - 5/x² - 3x + 2 = 6/x. ⇒ 3x² - 5x = 6x² - 18x + 12. ⇒ 3x² - 13x + 12 = 0.

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