Question

x^6 - x^2 = 2431 where x is an integer. how many values of x exist?​

Answer 1

Answer:

Consider the first inequality

2x+3>7

2x>4

x>2 ...(i)

Consider the second inequality

x+4<10

x<6 ...(ii)

From (i) and (ii), we have

x∈(2,6) ...(2 and 6 is not included since 2<x<6)

It is given that x is an integer.

Therefore integers lying between (2,6) (2 and 6 not included) are 3,4,5.

Hence, the integral values of x satisfying the above given linear inequalities are 3,4,5.

Step-by-step explanation:

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