Question

(x-6)(x+7)=(x-11)(x+3) solve this

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Answer 1

QUESTION:- (x-6)(x+7)=(x-11)(x+3)

ANSWER:-

$(x - 6)(x + 7) = (x - 11)(x + 3)$

$For \: L.H.S \:(x-6) \: will \: be \: multiplied \: by \: (x+7)$

$And, \: for \: R.H.S \: (x-11)(x+3) \: will \: be \: multiplied \: by \: (x+3)$

So, Now

$x {}^{2} + 7x - 6x - 42 = x {}^{2} + 3x - 11x - 33$

Now, solving the equation

$x {}^{2} + x - 42 = x {}^{2} - 8x - 33$

Taking variables on one side and numbers on other side

$x {}^{2} - x {}^{2} + x +8x = - 33 + 42$

$x {}^{2} \: got \: cancelled$

$- 9x = 9$

$x = - \frac{\cancel9}{\cancel9}$

$x= - 1$

HOPE IT HELPS✌

Answer 2

Step-by-step explanation:

1 is the correct answer of this question