Question

(x-6)(x+7)=(x+3)(x-11) Find the x

Answer 1

Answer:

answere of the wuestion is 1

Step-by-step explanation:

x^2+7x-6x-42=x^2-11x+3x-33

x^2+x-42      =x^2-8x-33

x2+x+8x-42+33=x2

x2 eliminates

9x-9=0

x=1

Answer 2

$(x - 6)(x + 7) = (x + 3)(x - 11) \\ \\ {x}^{2} - 6x + 7x - 42 = {x}^{2} + 3x - 11x - 33 \\ \\ {x}^{2} - {x}^{2} - 6x + 7x + 11x - 3x = - 33 + 42 \\ \\ - 9x + 18x = - 33 + 42 \\ \\ 9x = 9 \\ \\ x = \frac{9}{9} \\ \\ x = 1$

➡ Hence, x = 1

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