Question

x/6+y/15=4 x/3-y/12=19/4

Answer 1

given,

x / 6 + y / 15 = 4

so now ,

1 / 3 ( x / 2 + y / 5 ) = 4

x / 2 + y / 5 = 12 ------eq(1)

and given,

x / 3 - y / 12 = 19 / 4

1/ 3 (x / 1 - y / 4 ) = 19 / 4


x - y / 4 = 57 / 4 -----(2)

now multiply eq(1) by 1 and eq(2) by 1 / 2, we get ,

x / 2+ y / 5 = 12-----(3)

x / 2 - y / 8= 57 / 8----(4)
______________ subtract eq(4) from eq(3), we get ,


y/ 5 + y / 8 = 12 - 57 / 8

13 y / 40 = 39 / 8

y = 39 × 40 / 13 ×8

y = 3× 5 = 15

y = 15

now put value of "y" in eq.(1), we get

x / 2 + 15 / 5 = 12

x = 9 ×2 = 18

x = 18

hence value of x =18 , and y = 15
¶hope it helps ¶