Question

x/6+y/15=4,x/3-y/12=19 by cross multiplication method..​

Answer 1

Answer:

$1) \: \: \: \: \: \: \: \: \: \: \frac{x}{6} + \frac{y}{15} = 4 \\ \\ \frac{15x + 6y}{6 \times 15} = 4 \\ \\ 15x + 6y = 4 \times 6 \times 15 \\ \\ 15x + 6y = 360 \\ \\ 3(5x + 2y) = 360 \\ \\ (5x + 2y) = \frac{360}{3} \\ \\ 5x + 2y = 120\\ \\ \\ 2) \: \: \: \: \frac{x}{3} - \frac{y}{12} = 19 \\ \\ \frac{12x - 3y}{12 \times 3} = 19 \\ \\ 12x - 3y = 19 \times 12 \times 3 \\ \\ 3(4x - y) = 684 \\ \\ 4x - y = \frac{684}{3} \\ \\ 4x - y = 228$