Question

(x/6-y/5)^2 (expand using Suitable identities​

Answer 1

Answer:

$\left(\frac{x}{6}-\frac{y}{5}\right)^{2}=\frac{x^{2}}{36}-\frac{xy}{15}+\frac{y^{2}}{25}$

Step-by-step explanation:

$\left(\frac{x}{6}-\frac{y}{5}\right)^{2}$

$=\left(\frac{x}{6}\right)^{2}-2\times \frac{x}{6}\times \frac{y}{5}+\left(\frac{y}{5}\right)^{2}$

/* By algebraic identity:

(a-b)² = a²-2ab+b² */

$=\frac{x^{2}}{36}-\frac{xy}{15}+\frac{y^{2}}{25}$

Therefore,

$\left(\frac{x}{6}-\frac{y}{5}\right)^{2}=\frac{x^{2}}{36}-\frac{xy}{15}+\frac{y^{2}}{25}$

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