Question

x/6=y-6 3x/4=1+y solve by elimination method

Answer 1

Answer:

x=12

y=8

hope thus helps you❤

Answer 2

Answer:

Step-by-step explanation:

Concept:

The elimination approach involves taking one variable out of the system of linear equations by utilizing addition or subtraction together with multiplication or division of the variable coefficients.

One method for resolving a system of linear equations is the elimination method. In this approach, the equation in one variable is obtained by either adding or subtracting the equations. We can add the equation to delete a variable if its coefficients are the same and have the opposite sign from the other variables. Similar to this, we can subtract the equation to get the equation in one variable if the coefficients of one of the variables are the same and their signs are the same.

You can start by multiplying one or both equations by a constant value on both sides of an equation to obtain the equivalent linear system of equations, and then eliminate the variable by simply adding or subtracting equations if we do not have the equation to directly add or subtract the equations to do so.

Given:

$x/6=y-6$

$3x/4=y+1$

Find:

Solve the above equations by using elimination method.

Solution:

Consider the given equations

$x/6 =y-6 ........(i)eq$

$3x/4 = y+1 ........(ii)eq$

$x= 6y-36 ........(iii)$

Substitute (iii) eq in (ii) eq

$\frac{3(6y-36)}{4} =y+1$

$\frac{18y-108}{4} =y+1$

$18y-108=4y+4$

$18y-4y=4+108$

$14y=112$

$y=\frac{112}{14}$

$y=8$

Substitute y value in (iii) eq

$x=6y-36$

$x=6(8 )-36$

$x=48-36$

$x=12$

Hence $x=12 , y=8$

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