Question

X =( 6t^3 -3t^2 +2t-1) find velocity when acceleration is zero?

Answer 1

Answer:

1.5m/s

Explanation:

v=18t^2 -6t +2

a=36t -6=0

36t=6

t=1/6

putting t in v

v=18(1/6)^2 -6(1/6) +2

v=0.5 -1 +2

v=1.5 m/s