Question

x^ +6x +5 =0 where "6" is:
a. constant. b. coefficient
c. variables. d. value of x​

Answer 1

Step-by-step explanation:

The values of x are -1 and -5.

Step-by-step explanation:

The quadratic equation is

x^2+6x+5=0x

2

+6x+5=0

Comparing this equation with ax^2+bx+c=0ax

2

+bx+c=0

a = 1, b = 6, c = 5

The quadratic formula is given by

x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}x

1,2

=

2a

−b±

b

2

−4ac

Substituting the values

\begin{gathered}x_{1,\:2}=\frac{-6\pm \sqrt{6^2-4\cdot \:1\cdot \:5}}{2\cdot \:1}\\\\\=frac{-6\pm\sqrt{16}}{2}\\\\=\frac{-6\pm4}{2}\\\\\frac{-6+4}{2},\frac{-6-4}{2}\\\\=-1,-5\end{gathered}

The values of x are -1 and -5.