Question

X^-6x+8 find the zeros of the polynomials

Answer 1

Solution :

To find the zeroes of the polynomials,

Step : 1

Factorise the given polynomial x² - 6x + 8.

$\sf x^2 - 6x + 8$

$\sf= x^2 - ( 4 + 2 )x + 8$

$\sf = x^2 - 4x - 2x + 8$

$\sf= x (x-4)-2(x-4)$

$\sf= (x-2)(x-4)$

Now,

Step : 2

For finding zeroes of the polynomial,

→ x - 2 = 0

∴ x = 2

Also,

→ x - 4 = 0

∴ x = 4

Hence, zeroes of the polynomial are 2 and 4.

$\rule{200}2$