Question

x+6y+1 =0 ,2x+3y+8=0 ,x=? ,y=?​

Answer 1

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Answer 2

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$x + 6y+ 1 = 0 \\ x + 6y = - 1 \: \: \: \: \: \: \: \: \: \: \: \: \: -------(1) \\ \\ \\ 2x + 3y + 8 = 0 \\ 2x + 3y = - 8\: \: \: \: \: \: \: \: \: \: \: \: \: -------(2)$

$.°. \: \: \: \: \: \: x = - 1 - 6y \\\: \: \: \: \: \: \: \: \: \: \: \: \: \: \:= - 1(1 + 6y)$


Putting value of x in equation (2), we get,



$2( - 1 - 6y) + 3y = - 8 \\ \\ - 2 - 12y + 3y = - 8 \\ \\ - 1(2 + 12y - 3y) = - 8 \\ \\ 2 + 12y - 3y = \frac{ - 8}{ - 1} \\ \\ 2 + 12y - 3y = 8 \\ \\ 2 + 9y = 8 \\ \\ 9y = 8 - 2 \\ 9y = 6 \\ { \boxed{y = \frac{6}{9} = \frac{2}{3}}}$


Hence,

${ \huge{Value \: \: of \: \: x \: = \: - 1(1 + 6y)}} \\ \\ \\ \\ { \huge{\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = - 1(1 + \frac{6 \times 2}{3}) }}\\ \\ \\ \\ { \huge{\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = -1(1 + 4) }}\\ \\ \\ \\ { \huge{\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = - 1 \times 5 }}\\ \\ \\ \\{ \huge{\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = - 5}} \\ \\ \\ \\ \\ { \huge{Value \: \: of \: \: y \: = \frac{2}{3} }}$