X +6y =22, 3x +14y=58
in substitute method
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Answer:
GIVEN:-
X + 6Y = 22 &. 3X + 14Y = 58
so,
X= 22 - 6Y--------( Equation i)
and,
3X + 14Y = 58
putting value (i)
=> 3( 22 - 6Y ) + 14Y = 58
=> 66 - 18Y + 14Y = 58
=> 66 - 4Y = 58
=> 4Y = 66 - 58
=> Y = 8/4
=> Y = 2------------ ( Equation ii )
putting value (ii)
=>X + 6 x 2 = 22
=> X + 12 = 22
=> X = 10
Answer:- value of X= 10
Y=2
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