X+6y=5z, x+z=6y, 5x+6y-4z=24 please answer my question, subject (determinants) +2 commerce
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Answer:
Given Train starts at the same time.
Hence, Time remains constant.
Speed of Train 'T1' be 'S1' = 40 km\hr
Speed of Train 'T2' be 'S2' = 45 km\hr
Let X be the distance at which trains meet.
Train T2 travels X+40 km more than Train T1
Step-by-step explanation:
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