x-6y=7; if y=1,find x=?
Answers
Answered by
0
Step-by-step explanation:
Answer
The given equation is 4x+6y−7=0
⇒4x+6y=7$$
Dividing both sides by 7, we get
⇒
7
4x
+
7
6y
=1
⇒
4
7
x
+
6
7
y
=1 which is the required intercept form.
Here x−intercept=a=
4
7
and x−intercept=b=
6
7
∴The length of the segment intercepted between the axes=
a
2
+b
2
=
(
4
7
)
2
+(
6
7
)
2
=7
4
1
+
36
1
=7
4×36
36+4
=7
2×6
40
=7
12
2
10
=
6
7
10
units
Answered by
0
Answer:
x=13
Step-by-step explanation:
x-6y=7
as y =1
then, x-6(1)= 7
x-6=7
x=13
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