Math, asked by uramilasuvangiya, 1 day ago

x-6y=7; if y=1,find x=?​

Answers

Answered by angelkalta001
0

Step-by-step explanation:

Answer

The given equation is 4x+6y−7=0

⇒4x+6y=7$$

Dividing both sides by 7, we get

7

4x

+

7

6y

=1

4

7

x

+

6

7

y

=1 which is the required intercept form.

Here x−intercept=a=

4

7

and x−intercept=b=

6

7

∴The length of the segment intercepted between the axes=

a

2

+b

2

=

(

4

7

)

2

+(

6

7

)

2

=7

4

1

+

36

1

=7

4×36

36+4

=7

2×6

40

=7

12

2

10

=

6

7

10

units

Answered by abhinavsingh55758
0

Answer:

x=13

Step-by-step explanation:

x-6y=7

as y =1

then, x-6(1)= 7

x-6=7

x=13

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