(x-7)/3=(x-1)/5
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KunalTheGreat:
this question is for my sis was lazy to answer it :D
Answers
Answered by
11
Hey there!
(x-7)/3 = (x-1)/5
Transposing the denominators.
5(x-7) = 3(x-1)
5x -35 = 3x - 3
5x -3x = -3 + 35
2x = 32
x = 32/2 = 16 .
Hope helped !
(x-7)/3 = (x-1)/5
Transposing the denominators.
5(x-7) = 3(x-1)
5x -35 = 3x - 3
5x -3x = -3 + 35
2x = 32
x = 32/2 = 16 .
Hope helped !
Answered by
1
Hi friend
---------------
Your answer
---------------------
(x - 7)/3 = (x - 1)/5
=> 5(x - 7) = 3(x - 1)
=> 5x - 35 = 3x - 3
=> 5x - 3x = - 3 + 35
=> 2x = 32
=> x = 32/2
=> x = 16
HOPE IT HELPS
---------------
Your answer
---------------------
(x - 7)/3 = (x - 1)/5
=> 5(x - 7) = 3(x - 1)
=> 5x - 35 = 3x - 3
=> 5x - 3x = - 3 + 35
=> 2x = 32
=> x = 32/2
=> x = 16
HOPE IT HELPS
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