Question

(x+7)(x+5)(x+8) using algebraic identity find the coeffient of x square and x and constant term without actual expression

Answer 1

Answer:

coefficient of x^2is 20, coefficient of x is 119 and the constant term is 280

Step-by-step explanation:

(x+7)(x+5)(x+8)=[x(x+5)+7(x+5)](x+8)

=[x^2+5x+7x+35](x+8)

=[x^2+12x+35](x+8)

=x(x^2+12x+35)+8(x^2+12x+35)

=x^3+12x^2+35x+8x^2+84x+280

=x^3+20x^2+119x+280