Question

(x+7) (x-8)=0
(x-3) (x-7)=0

Answer 1

h$(x +7 )(x - 8) = 0 \\ x {}^{2} - 8x - 7x - 56 = 0 \\ x {}^{2} - 15x - 56 = 0 \\ then \: factorise \\ (x - 3)(x - 7) = 0 \\ x {}^{2} - 7x - 3x + 21 = 0 \\ x {}^{2} - 10x + 21 = 0 \\ then \: factorise$