Question

x/7+y/3=5 x/2-y/9=6 by elimination method​

Answer 1

The eqn are simplified and then eqn ii is multiplied with suitable coefficient.
Hope it helps

Answer 2

GIVEN :

The equations are $\frac{x}{7}+\frac{y}{3}=5$ and $\frac{x}{2}-\frac{y}{9}=6$

TO SOLVE :

The given equations by Elimination Method

SOLUTION :

Given equations can be written as below

$\frac{x}{7}+\frac{y}{3}=5$

$3x+7y=5\times 21$

$3x+7y=105\hfill (1)$

and

$\frac{x}{2}-\frac{y}{9}=6$

$9x-2y=6\times 18$

$9x-2y=108\hfill (2)$

Now solving the equations (1) and (2) we have

Multiply the equation (1) into 3 we get

$9x+21y=315\hfill(3)$

Now subtracting the equations (2) and (3) we get

$9x-2y=108$

$9x+21y=315$

(-)__(-)__ (-)_______

     $-23y=-207$

$y=\frac{207}{23}$

$=9$

∴ y=9

Substituting the value of y in equation (1) we get

$3x+7(9)=105$

$3x+63=105$

$3x=105-63$

$x=\frac{42}{3}$

$=14$

∴ x=14

The values of x and y is 14  and 9 respectively

The solution is (14,9).