x^-7x-44=0 what is value of x
Answers
Answered by
3
Begin with writing the equation into brackets.
(x+a)(x+b)=0
You want to find a and b such that a+b=7and a⋅b=−44.
Through a process of trial and error, this gives a=−4 and b=11.
(x−4)(x+11)=0
Anything multiplied by 0 is 0, meaning at least one of the brackets has to be equal to 0. This actually gives two answers for x. Set each one equal to zero and then solve.
x−4=0
x=4
or
x+11=0
x=−11
(x+a)(x+b)=0
You want to find a and b such that a+b=7and a⋅b=−44.
Through a process of trial and error, this gives a=−4 and b=11.
(x−4)(x+11)=0
Anything multiplied by 0 is 0, meaning at least one of the brackets has to be equal to 0. This actually gives two answers for x. Set each one equal to zero and then solve.
x−4=0
x=4
or
x+11=0
x=−11
Answered by
1
Hello user☺☺
It will be .....
x^2 -7x -44 = 0
x^2 - 11x + 4x - 44 =0
x(x-11) + 4(x-11) = 0
(x+4)(x-11) = 0
So, x = -4 and x = 11.
Hope it works☺☺
It will be .....
x^2 -7x -44 = 0
x^2 - 11x + 4x - 44 =0
x(x-11) + 4(x-11) = 0
(x+4)(x-11) = 0
So, x = -4 and x = 11.
Hope it works☺☺
Anonymous:
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