Question

x+7y=10 ; 3x-2y=7 solve the following with simultaneous e

Answer 1

Given :-

$x + y = 10.....................(i) \\ and \\ 3x - 2y = 7....................(ii)$

Multiplying equation (i) by 2 and equation (ii) by 7, we get

$2x + 14y = 20......................(iii) \\ and \\ 21x - 14y = 49....................(iv)$

Solving equations (iii) and (iv), we get

$23x = 69 \\ \\ = > x = 3$

Putting the value of x in equation (i), we get

$3 + 7y = 10 \\ \\ = > 7y = 7 \\ \\ = > y = 1$


Thus, we have

x = 3

and

y = 1

Answer 2

Answer:

value of x and y are 3,1 respectively.

Step-by-step explanation:

The given equations are:

  x+7y=10                   (1)

and 3x-2y=7               (2)

Now, multiply equation (1) with 3 and subtract the equation (2) from the obtained new equation.

⇒3x+21y-3x+2y=30-7

⇒23y=23

⇒y=1

Now, substituting the value of y=1 in equation (1), we get

⇒x+7(1)=10

⇒x=10-7

⇒x=3

Thus, value of x and y are 3,1 respectively.