X+7y=10 ; 3x-7y=7 solve the following
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Answer:
let
x+7y=10 is a eq1
3x-7y=7 is a eq2
from eq 1
x=10-7y
put x=19-7y in eq 2
Answered by
2
Answer:
x + 7y = 10; .....(I)
3x – 2y = 7 .....(II)
Multiplying (I) with 3
3x + 21y = 30; .....(III)
3x – 2y = 7 .....(IV)
Subtracting (IV) from (III) we get
23y = 23
⇒y = 1
Putting the value of y in (IV) we get
3x – 2 = 7
⇒3x = 7 + 2 = 9
⇒3x = 9
⇒x = 3
Thus, (x, y) = (3, 1)
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