Question

X- 7Y+42= 0 and X-3Y-6=0. Find the values of X and Y.

Answer 1

Answer:

X = 42

Y = 12

Hope this helps.....

Answer 2

${ \tt{ \large {question \colon}}}$

${ \rm{x - 7y + 42 = 0}}$

${ \rm{x + 3y - 6= 0}}$

${ \tt{ \large{solution \colon}}}$

${ \rm{x - 7y + 42 = 0 \to(i)}}$

${ \rm{x + 3y - 6= 0 \to(ii)}}$

${ \rm{x - 7y = ( - 42) \to(i)}}$

${ \rm{x + 3y = 6 \to(ii)}}$

${ \rm{comparing \:eqa.(i) \: and \: (ii)}}$

$\sf {\not{x}\ -\ 7y\ =\ -\ 42}\\ \not{-x} \ +\ 3y\ =\ -\ 6 \\ </p><p> ────────────────── \\ - 4y = - 48 \\ </p><p>$

${ \rm{y = \dfrac{48}{4} = 12 }}$

${ \rm{putting \: the \: value \: of \: y \: in \: eq.(i)}}$

${ \rm{x - 7 y = (- 42) \to(i)}}$

${ \rm{ \implies x - 7 \times 12 = ( - 42)}}$

${ \rm{ \implies x -84 = ( - 42)}}$

${ \rm{ \implies x = ( - 42) + 84}}$

${ \rm{ \implies x = 42}}$

${ \rm{the \: value \: of \: x = 12 \: and \: y = 42}}$