x^8-1 how to solve this using identites by factorisation
Answers
Answer:
हिंदी में खोजें
factorise एक्स 8-1
How to solve your question
Your question is
8
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x^{8}-1
x8−1
Grouping
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Find one factor
Factor by grouping
Factor by grouping
Factor by grouping
Factor by grouping
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{\color{#c92786}{({\color{#c92786}{x-1}})({\color{#c92786}{x^{7}+x^{6}+x^{5}+x^{4}+x^{3}+x^{2}+x+1}})}}
(x−1)(x7+x6+x5+x4+x3+x2+x+1)
2
Find one factor
Factor by grouping
Factor by grouping
Factor by grouping
Factor by grouping
Factor by grouping
Factor by grouping
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(x-1)({\color{#c92786}{x+1}})({\color{#c92786}{x^{6}+x^{4}+x^{2}+1}})
(x−1)(x+1)(x6+x4+x2+1)
3
Find one factor
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Factor by grouping
Factor by grouping
Factor by grouping
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(x-1)(x+1)({\color{#c92786}{x^{2}+1}})({\color{#c92786}{x^{4}+1}})
(x−1)(x+1)(x2+1)(x4+1)
Solution
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Answer:
x^8-1
(x^4-1^4)(x^4+1^4)
(x^2-1^2)(x^2+1^2)(x^4+1^4)
(x-1)(x+1)(x^2+1)(x^4+1)....