Math, asked by santoshh2006gmailcom, 4 months ago

[x^8]^8×[(y^3)^2]^8/[x^16]^2×[y]^6
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Answers

Answered by ManishShah98
1

Answer:

[x^8]^8×[(y^3)^2]^8/[x^16]^2×[y]^6 ; [(a^2)^2 = a^4]

x^64 × y^48 / x^32 × y^6 ; [ a^1/a^1 = a^1-1]

x^64-32 × y^48-6

x^32 × y^42 Answer

given formula.........

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