Question

x^+8x-48=0

solve it by completing square method

Answer 1

Hey mate...☺☺

Here is ur ans...✌✌

${x}^{2} + 8x - 48 = 0 \\ \\ by \: middle \: term \: spliting \: method \\ \\ {x}^{2} + 12x - 4x - 48 = 0 \\ \\ x(x + 12) - 4(x + 12) \\ \\ (x - 4)(x + 12) \\ \\ so \: now \: it \: is \: solved$

Hope it helps u...❤❤

Thanks...✌✌