Question

X=9^1/3 and y=cube root of 8 find X+y-1/x^2+xy+y^2

Answer 1

Answer:

14.889

Step-by-step explanation:

x=9^1/3, y=cube root of 8

x=9/3=3;y=2

x+y-1/x^2+xy+y^2

3+2-1/3^2+3*2+2^2

5-1/9+6+4

5-1/9+10

15-1/9

(135-1)/9

134/9

14.889

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