Question

x+9, x-6 and 4 are three consecutive terms of a G.p​

Answer 1

terms of GP = 25 ,10 ,4

a = x +9

b = x -6

c = 4

If a,b,c are consecutive terms of GP

b^2 = ac

(x - 6 ) ^2 = ( x+ 9 ) × 4

x^2 - 12 x + 36 = 4x + 36

x^2 - 16 x = 0

x^2 = 16 x

x = 16

terms of GP

a = 16 + 9 = 25

b = 16 - 6 = 10

c = 4