x+9y-z=4
2x+7y+3z=7
3x+10y+4z=9
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the first equation take as one, and the second, third
equation one we have to multiple with 3 than
3x+27y-3z=12
2x+7y+3z=7
the z term will cancel
5x+34y=19 this take as 4 equation
equation one multiple with 4 then
4x+36y-4z=16
3x+10y+4z=9
the z term will cancel
7x+46y=25 take as 5 equation
4&5th equation as
4th equation as multiple as 7&5th equation as multiple as 5th
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