(x/a)^2/3+(y/b)^2/3=1 find the derivative
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Lengthofacurvey−f(x)fromatobis
L=x=a∫b1+(dxdy)2dx
Given
(ax)2/3+(by)2/3=1
L=4×lengthofcurvefromx=0toa
L=4×l
l=0∫a1+(dxdy)2dx
(by)2/3=1−(ax)2/3
⇒by=[1−(
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