X = √a^3.√b√a^3√b- - - infinity
find the value of X
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Step-by-step explanation:
Let √3+√3+√3+√3…………=x In that case,
√3+x=x {As in an infinite series taking one term out doesn’t make a difference
(remember that it is root over (3+x) but not √3+x)}
Squaring on both sides :
(√3+x)^2=x^2
x^2= x+3
X^2-x-3=0
x= 1+_√1+12\/2
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Answer:
Step-by-step explanation:
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