[{x^a(a-b)/x^a(a+b)}÷{x^b(b-a)/x^b(b+a)}]^a+b=1
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Answer:
[ x^(a²-ab-a²-ab) / x^(b²-ab-b²-ab) ]^(a+b)
=[ x^-2ab / x^-2ab ]^(a+b)
=( x^(-2ab+2ab) )^(a+b)
=(x^0)^(a+b)
=1^(a+b)
=1
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