Math, asked by ashwaniryadav, 5 months ago

(x/a-a/x)^2n ka (r+1)वा पद ज्ञात कीजिए​

Answers

Answered by ÇríSTyBūttĒrfLy
1

Answer:

sorry I can't understand it

Answered by mohammedsinan6499
1

Answer:

Answer-

( identity : (a-b)² = a²-2ab +b²)

= {(2x - 5y)}^{2}=(2x−5y)

2

= {(2x)}^{2} - 2(2x)(5y) + {(5y)}^{2}=(2x)

2

−2(2x)(5y)+(5y)

2

= 4 {x}^{2} - 20xy + 25 {y}^{2}=4x

2

−20xy+25y

2

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