(x^a-b)^1/ab * (x^b-c)^1/bc * (x^c-a)^1/ca
If possible please give the answer in paper
(No problem if you can't)
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Answer:
= (xa/xb)1/ab( xb /xc)1/bc(xc/xa)1/ca
= x^(a-b)/ab * x^(b-c)/bc * x^(c-a)/ca
= x^[(a-b)/ab + (b-c)/bc + (c-a)/ca]
= x^[c(a-b)/abc + a(b-c)/abc + b(c-a)/abc ]
= x^ { [c(a-b)+ a(b-c) + b(c-a) ]/abc }
= x ^( ac – bc + ab – ac + bc – ab ] /abc
= x^ 0/abc
= x^0
= 1
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