Question

x^(a+b) ^2(x^(b+c)^2(x^(c+a)^2/(x^ax^bx^c)​

Answer 1

Answer:

In above equation, to convert the denominator in terms variable in numerator only, substitute,  a+b+c=y  

So, above equation becomes,

x−a2y−a+x−b2y−b+x−c2y−c=4y  

Just for a the sake of cancelling the denominator terms, substitute  x=y2  in this, so we get

y2−a2y−a+y2−b2y−b+y2−c2y−c=4y  

(y−a)(y+a)(y−a)+(y−b)(y+b)(y−b)+(y−c)(y+c)(y−c)=4y  

(y+a)+(y+b)+(y+c)=4y  

3y+a+b+c=4y  i.e.  y=a+b+c  

So, this is the same value as per our assumption which is indeed found to be true.

Hence,  x=y2  i.e.  x=(a+b+c)2  is the solution of above equation.

Hope This Helps you