(x^a+b)^a-b × (x^b+c)^b-c × (x^c+a)^c-a = 1
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Answer:
= (xa+b)a-b .(xb+c)b-c. (xc+a)c-a
= x(a+b)(a-b). x(b+c)(b-c) .x(c+a)(c-a)
= x0
Step-by-step explanation:
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