Question

(x^a-b)^a+b(x^b-c)^b+c(x^c+a)^c+a=1 prove​

Answer 1

Answer:

I hope clear your answer

Answer 2

Answer:

PROVED

Step-by-step explanation:

(x^a-b)^a+b(x^b-c)^b+c(x^c-a)^c+a

=(x^a^2-b^2)( x^b^2-c^2)( x^c^2-a^2)

=x^(a^2-b^2+b^2-c^2+c^2-a^2)

=x^0

= 1 ( proved )