Question

(x^a+b)^a-b .(x^b+c)^b-c.(x^c+a)^c-a

Answer 1

Answer:

1

Step-by-step explanation:

$(x^{a+b} )^{a-b}$ * $(x^{b + c} )^{b - c}$ * $(x^{c + a} )^{c - a}$

= $x^{a^{2} -b^{2} }$ * $x^{b^{2} - c^{2} }$ * $x^{c^{2} - a^{2} }$

= $x^{a^{2}- b^{2}+ b^{2} -c^{2} +c^{2} -a^{2}  }$

= $x^{0}$

=1