Question

(X^a+b)^a-b . (X^b+c)^b-c . (X^c+a)^c-a

Answer 1

Step-by-step explanation:

Simplify (xa + b)a-b .(xb + c)b-c.(xc+a)c-a

= (xa+b)a-b .(xb+c)b-c. (xc+a)c-a = x(a+b)(a-b). x(b+c)(b-c) .x(c+a)(c-a) = x0

Answer 2

Answer:

x^(a+b)(a-b)×x^(b+c)(b-c)×x^(c+a)(c-a)

u can use the formula (a+b)(a-b)=a^2-b^2

then the numerator will be cancelled totally

finally u will get x^0=1